5^x+2/5^-3x=125

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Solution for 5^x+2/5^-3x=125 equation: 



5^x+2/5^-3x=125

We move all terms to the left:

5^x+2/5^-3x-(125)=0

determiningTheFunctionDomain
5^x-3x-125+2/5^=0

We add all the numbers together, and all the variables

-3x+5^x-125+2/5^=0

We multiply all the terms by the denominator


-3x*5^+5^x*5^+2-125*5^=0

We add all the numbers together, and all the variables

-3x*5^+5^x*5^=0

Wy multiply elements

-15x^2+25x^2=0

We add all the numbers together, and all the variables

10x^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{20}=0$

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